5y^3-19y^2-4y=0

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Solution for 5y^3-19y^2-4y=0 equation:


Simplifying
5y3 + -19y2 + -4y = 0

Reorder the terms:
-4y + -19y2 + 5y3 = 0

Solving
-4y + -19y2 + 5y3 = 0

Solving for variable 'y'.

Factor out the Greatest Common Factor (GCF), 'y'.
y(-4 + -19y + 5y2) = 0

Factor a trinomial.
y((-1 + -5y)(4 + -1y)) = 0

Subproblem 1

Set the factor 'y' equal to zero and attempt to solve: Simplifying y = 0 Solving y = 0 Move all terms containing y to the left, all other terms to the right. Simplifying y = 0

Subproblem 2

Set the factor '(-1 + -5y)' equal to zero and attempt to solve: Simplifying -1 + -5y = 0 Solving -1 + -5y = 0 Move all terms containing y to the left, all other terms to the right. Add '1' to each side of the equation. -1 + 1 + -5y = 0 + 1 Combine like terms: -1 + 1 = 0 0 + -5y = 0 + 1 -5y = 0 + 1 Combine like terms: 0 + 1 = 1 -5y = 1 Divide each side by '-5'. y = -0.2 Simplifying y = -0.2

Subproblem 3

Set the factor '(4 + -1y)' equal to zero and attempt to solve: Simplifying 4 + -1y = 0 Solving 4 + -1y = 0 Move all terms containing y to the left, all other terms to the right. Add '-4' to each side of the equation. 4 + -4 + -1y = 0 + -4 Combine like terms: 4 + -4 = 0 0 + -1y = 0 + -4 -1y = 0 + -4 Combine like terms: 0 + -4 = -4 -1y = -4 Divide each side by '-1'. y = 4 Simplifying y = 4

Solution

y = {0, -0.2, 4}

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